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-1=0.3x^2-x-8
We move all terms to the left:
-1-(0.3x^2-x-8)=0
We get rid of parentheses
-0.3x^2+x+8-1=0
We add all the numbers together, and all the variables
-0.3x^2+x+7=0
a = -0.3; b = 1; c = +7;
Δ = b2-4ac
Δ = 12-4·(-0.3)·7
Δ = 9.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{9.4}}{2*-0.3}=\frac{-1-\sqrt{9.4}}{-0.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{9.4}}{2*-0.3}=\frac{-1+\sqrt{9.4}}{-0.6} $
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